Question

Решите номер 108.Есть вложение.

Answer 1

1/5c+1/10c=3/10c
(3/10c)*(c^2/6)=(3/10*c)*(c*c/3*2)=c/20

Answer 2

$( frac{1}{5c} + frac{1}{10c} )cdot frac{c^2}{6} = ( frac{2}{10c} + frac{1}{10c} )cdot frac{c^2}{6} = frac{3}{10c} cdot frac{c^2}{6} = frac{3c^2}{6cdot 10c} = frac{c}{20}$