Question

Решите номер 98.Есть вложение.

Answer 1

$frac{c-3}{c} - frac{c^2-9}{c} cdot frac{1}{c-3} = frac{c-3}{c} - frac{(c-3)(c+3)}{c(c-3)} = frac{c-3}{c} - frac{c+3}{c} = frac{c-3-c-3}{c} =- frac{6}{c}$