Question

Решите номер 81.Есть вложение.

Answer 1

$frac{x^2+2xy+y^2}{x^2-y^2} :(x+y)= frac{(x+y)^2}{(x-y)(x+y)} cdot frac{1}{(x+y)} = frac{(x+y)^2}{(x-y)(x+y)(x+y)}= frac{1}{x-y}$