Question

f(x)=3x^6-2x^4, f'(x)=0

Answer 1

$f'(x)=(3x^6)'-(2x^4)'=18x^5-8x^3 \ 18x^5-8x^3=0 \ 2x^3(9x^2-4)=0 \ x_1=0 \ 9x^2-4=0 \ x=pm frac{2}{3}$