Question

1/(x-2)^2 - 3/(x-2) - 4 =0

Answer 1

$frac{1}{(x-2)^2} - frac{3}{x-2} -4=0|cdot (x-2)^2 \ 1-3(x-2)-4(x-2)^2=0 \ 1-3x+6-4x^2+16x-16=0 \ 4x^2-13x+9=0 \ D=b^2-4ac=169-4cdot 4cdot 9=25 \ x_1=1 \ x_2=2.25$