Question

(x^2-5x+7)^2-2*(x-2)*(x-3)=1

Answer 1

(x^2-5x+7)^2-2*(x^2-5x+6)=1

замена (x^2-5x+7)=t?  (x^2-5x+6)=t-1

t^2-2*(t-1)-1=0

t^2-2t+1=0

(t-1)^2=0

t-1=0

t=1

(x^2-5x+7=1

(x^2-5x+6=0

x1=2  x2=3