Question

$intlimits^ frac{ pi }{12} _0 {6cos6x} , dx intlimits^6_3 {7x^2} , dx$

Answer 1

1) $=6* frac{1}{6}* intlimits^{frac{ pi }{12}}_{0} {cos(6x)} , d(6x)=sin(6x)=sin(6*frac{ pi }{12})-sin0=sin(frac{ pi }{2})=1$

2) $=7* frac{x^{3}}{3}=7* frac{6^{3}}{3}-7* frac{3^{3}}{3}=504-63=441$