Question

(9x^4)^5*(3x)^3 / (27x^5)^4=-192

Answer 1

$frac{(9x^4)^5*(3x)^3}{(27x^5)^4}=-192\frac{(3^{10}x^{20})*(3^3x^3)}{3^{12}x^{20}}=-192\3^{10+3-12}*x^{20+3-20}=-192\3x^3=-192\x^3=-64\x=-4$