Question

Найти значение выражения cos⁡(- π/6)+ctg(- 3π/2)- sin⁡(- π/3)+ ctg(-π/4)

Answer 1

cos⁡(- π/6)+ctg(- 3π/2)- sin⁡(- π/3)+ ctg(-π/4)=√3/2-0+√3/2-1=2√3/2-1=√3-1≈1,73-1≈0,73

Answer 2

cos⁡(- π/6)+ctg(- 3π/2)- sin⁡(- π/3)+ ctg(-π/4) = cos π/6 - ctg 3π/2 + sin π/3 - ctg π/4 = √3/2 - 0 + √3/2 -1 = √3 - 1