Question

Помогите!!!!!!!!!!!!!!!!1

Answer 1

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Answer 2

1. 2a/(a+3) - 4a/(a^2+6a+ 9)= 2a^2+6a-4a/(a+3)^2=2a(a+1)/(a+3)^2
2. 2a(a+1)/(a+3)^2 : a+1/a^2-9 =2a(a-3)/(a+3)
3.2a(a-3)/ (a+3) * a^2-9a/(a+3)= 2a^2 -6a - a^2-9a/(a+3)=a^2+3a/(a+3)=a(a+3)/(a+3) = a