Предмет: Геометрия, автор: Лика199801

помогите решить задачку! вычислите площадь прямоугольной трапеции, основания которой равны 2см и 4 см, а один из углов равен 45 градусов

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Автор ответа: KrOsNeVeR

0

допустим что трапеция называется ABCD тогда проводим высоту из точки C к стороне AD .Назовем её CH получился квадрат со сторонами 2 см и рарнобедренный треуголиник дальше находим площадь по формуле S=((a+b)*h) делим всё это на 2 S=((2+4)*2) :2 =6см

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