Question

(6x^2-3xz+10x-5z/3x^2+5x)+(z/x)

Answer 1

$frac{6x^{2}-3xz+10x-5z}{3x^{2}+5x}+frac{z}{x}=frac{3x(2x-z)+5(2x-z)}{x(3x+5)}+frac{z}{x}=$

 

$=frac{x(3x+5)(2x-z)+zx(3x+5)}{x(3x+5)}=frac{x(3x+5)(2x-z+z)}{x(3x+5)}=2x$