Question

$frac{sin(x)}{1-cos(x)} = frac{1+cos(x)}{sin(x)}$
Помогите доказать данное тождество

Answer 1

$frac{sinx*sinx-(1+cosx)(1-cosx)}{sinx(1-cosx)} =0$
$frac{sin^2x-(1-cos^2x)}{sinx(1-cosx)} =0$
$frac{sin^2x-sin^2x}{sinx(1-cosx)} =0$
$frac{0}{sinx(1-cosx)} =0$
$0=0$, чтд.