Question

Помогите решить!

3sin^2x+5sinx+2=0

Answer 1

3sin²x + 5sinx + 2 = 0
sinx  = z
3z² + 5z + 2 = 0
D = 25 - 4*3*2 = 1
z₁ = (- 5 - 1)/6
z₁ = - 1
(-5 + 1)/6
z₂ = - 4/6
z₂ = - 2/3
1) sinx = - 1
x₁ = - π/2 + 2πk, k ∈Z
2) sinx = - 2/3
x₂ = (-1)^(n)arcsin(-2/3) + πn, n∈Z