Question

sin3x+sin5x+2sin^2x/2=1
помогите плиз)

Answer 1

$sin3x+sin5x+2sin^2 frac{x}{2} =1 \ sin3x+sin5x+1-cos x=1 \ 2sin 4xcdot cos x-cos x=0 \ cos x(2sin4x-1)=0 \ left[begin{array}{ccc}cos x=0\sin4x= frac{1}{2} end{array}rightto left[begin{array}{ccc}x_1= frac{ pi }{2} + pi n,n in Z\ x_2=(-1)^kcdot frac{ pi }{4}+ frac{ pi k}{4}, k in Z end{array}right$