Предмет: Химия, автор: Лигай

Rакой объем (при н.у) кислорода необходим для полного сжигания 5м3 метана CH4&

Ответы

Автор ответа: Christina98

Дано:

CH4

V(CH4)=5м3

Найти:

V(O)=?

Решение:

CH4 + 2O2=CO2+2H2O

1моль 2 моль

22,4гмоль 44,8гмоль

5м3 Х

22,4гмоль5м3=44,8гмольх

х=44,8гмоль*5м322,4гмоль=10м3

Ответ:10м3

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