Question

ПОМОГИТЕ с уравнением
16y^2 - 49 = 0

Answer 1

$16y^2 - 49 = 0 \ (4y-7)(4y+7)=0 \ 4y-7=0 \ 4y=7 \ y=7/4 \ \ 4y+7=0 \ 4y=-7 \ y=-7/4 \ \ Otvet:7/4;-7/4$

Answer 2

D= 0+4*49*16=56^2
X1=(0-56)/32=-1,75
X2=56/32=1,75