Question

корень уравнения?8^4-x=64^2x

Answer 1

$8 ^{4-x} =64 ^{2x}$
ОДЗ: х∈R
$8 ^{4-x} =(8 ^{2} ) ^{2x}$
$8 ^{4-x} =8 ^{4x}$
4-x=4x
4=5x
x=0,8