Question

решите неравенство!!

1) 3x-4(2x-8) < -3

2) 6x-3(4x+1) > 6

Answer 1

$3x-8x+32 textless -3\\ -5x textless -3-32 \ \ -5x textless -35 \ \ x textgreater 7 \ \ \ 6x-12x-3 textgreater 6 \ \ -6x textgreater 6+3 \ \ -6x textgreater 9 \ \ x textless -frac{3}{2}$

Answer 2

1) 3x-4(2x-8) < -3
3x-8x+32<-3
-5x<-35
x>7
x∈(7;∞)
2) 6x-3(4x+1) > 6
6x-12x-3>6
-6x>9
x<-1,5
x∈(-∞;-1,5)