Question

100-(3a+7y)^2,1-(а^2+b^2)^2 разложите на множители

Answer 1

$100-(3a+7y)^2=10^2-(3a+7y)^2=(10+3a-7y)(10-3a-7y)\\1-(a^2+b^2)^2=1^2-(a^2+b^2)^2=(1-a^2-b^2)(1+a^2+b^2)$