Question

Найдите производную функции:

Answer 1

$f'(x)=(6cos^5(3-frac{1}{12}x^4))'=-6bullet5sin^4(3-frac{1}{12}x^4)bullet(3-frac{1}{12}x^4)'=\\=-30sin^4(3-frac{1}{12}x^4)bullet(-frac{4}{12}x^3)=10x^3sin^4(3-frac{1}{12}x^4).$