Question

ПОЖАЛУЙСТА РЕШИТЕ ХОТЬ ЧТО-ТО ПРОШУ

Answer 1

1)  y = log₂ (x + 2)
x + 2 > 0
x > - 2
D(y) = (-2 ; + ∞)
3)  a)  y = x³ - 2x
x₀ = - 2
y(-2) = (-2)³ - 2*(-2) = - 8 + 4 = - 4
b)  y = sin(2x - π/3) + 4
x₀ = π/6
y = sin(2π/6 - π/3) + 4 = sin(π/3 - π/3) + 4 = sin0 + 4 = 0 + 4 = 4
5)  y = 4x - 3
4x = y + 3
x = (y + 3)/4