Question

помогите, очень нужно

Answer 1

$-9(b^{4}-3b^{2}+6)$$(b^{2}-3)(b^{2}-3)^{2} - (b^{2}+3)(b^{4}-3b^{2}+9) =$

$(b^{2}-3)(b^{4}-6b^{2}+9) - (b^{2}+3)(b^{4}-3b^{2}+9) =$

$(b^{6}-6b^{4}+9b^{2}-3b^{4}+18b^{2}-27) - (b^{6}-3b^{4}+9b^{2}+3b^{4}-9b^{2}+27) =$

$b^{6}-9b^{4}+27b^{2}-27 - b^{6}-27 = -9b^{4}+27b^{2}-54=$

$-9(b^{4}-3b^{2}+6)$