Question

(1+4x/2x-3)'=? Помогите найти производную.

Answer 1

$f`(x)=(frac{1+4x}{2x-3})`=frac{(1+4x)`(2x-3)-(1+4x)(2x-3)`}{(2x-3)^{2}}=$

 

$=frac{4(2x-3)-(1+4x)*2}{(2x-3)^{2}}=frac{8x-12-2-8x}{(2x-3)^{2}}=frac{-14}{(2x-3)^{2}}$