Question

2-4у+у^2=-1. помогите пожалуйста

Answer 1

2-4y+y^2 = -1
y^2 - 4y + 2 + 1 = 0
y^2 - 4y + 3 = 0
D = (-4)^2 -4*3 = 16-12 = 4
√4 = 2
x1 = (4-2)/2 = 1
x2 = (4+2)/2 = 3 
Ответ: х1=1 ; х2 =  3 

Answer 2

2-4у+у²=-1
y²-4y+2+1=0
y²-4y+3=0
D=(-4)²-4*3*1=16-12=4=2²
$x_{1}= frac{-(-4)- sqrt{4} }{2*1}= frac{4-2}{2} = frac{2}{2} =1 \ x_{2}= frac{-(-4+ sqrt{4} }{2*1}= frac{4+2}{2} = frac{6}{2} =3$