Question

а)4sin^2(3x)<3

б)sin(2x)*cos(2x)<0,25

Answer 1

sin4x<1/8

П-arcsin1/8+2Пk<4x<2П+arcsin1/8+2Пk

П(2k+1)/4-1/4arcsin1/8<x<П/2(1+k)+1/4arcsin1/8

sin^23x<3/4

sinx<sqrt(3)/2

 

2/3П+2Пk<x<7П/32Пk

 

sinx>-sqrt(3)/2

2/3П+2Пk<x<4П/3+2Пk

U

5П/3+2Пk<x<7П/32Пk