Question

2cos30-ctg45+sin^2 60+ctg^2 60

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Answer 1

$2cos30-ctg45+sin^2 60+ctg^2 60=2*frac{sqrt{3}}{2}-1+(frac{sqrt{3}}{2})^2+(frac{1}{sqrt{3}})^2=\sqrt{3}-1+0,75+frac{1}{3}=sqrt{3}-frac{1}{4}+frac{1}{3}=sqrt{3}+frac{1}{12}$