Question

$frac{4}{9}$ x³-25x=0

Answer 1

$frac{4}{9} x^{3}-25x=0 \ 9(frac{4}{9} x^{3}-25x)=9*0 \ 4 x^{3}-225x=0 \ x(4 x^{2} -225)=0 \ \ x_{1}=0 \ \ 4 x^{2} -225=0 \ 4 x^{2}=225 \ x^{2} =56,25 \ x=+- sqrt{56,25} \ x_{2}= 7.5 \ x_{3}=-7.5$
Ответ: х₁=0,х₂=7,5, х₃= -7,5