Question

$25^{1-0,5 log_5 11$

Answer 1

$25^{1-0,5 log_5 11}=\(5^2)^{1-0,5 log_5 11}=\ 5^{2*(1-0,5 log_5 11)}=\5^{2-log_5 11}=\frac{5^2}{5^{log_5 11}}=frac{25}{11}$

Answer 2

$25^{1-0,5log_511}=5^{2-log_511}=frac{5^2}{5^{log_511}}=frac{25}{11}$