Question

Решите уравение:9х2+2х-1/3=0

Answer 1

$9x^2+2x-1/3=0\27x^2+6x-1=0\ d=36-4*27*(-1)=144\x=frac{-6бsqrt{144}}{54}\x_1=frac{-6+12}{54}=frac{1}{9}\x_2=frac{-6-12}{54}=-frac{1}{3}$