Question

Помогите:3 кисы❤️❤️❤️номер7

Answer 1

$frac{x^2}{x^2-3xy} : frac{x}{x^2-9y^2} = frac{x^2}{x(x-3y)} : frac{x}{(x-3y)(x+3y)} = \ \ = frac{x^2}{x(x-3y)} cdot frac{(x-3y)(x+3y)}{x} =x+3y \ \ x=5+3sqrt{6} y=2-sqrt{6} \ \ 5+3sqrt{6}+3cdot (2-sqrt{6})=5+3sqrt{6}+6-3sqrt{6}=11$

Answer 2

=x^2 / x(x-3y)   *    (x-3y)(x+3y) / x = x+3y  
5+3√6 + 3(2-√6)=5+3√6+6-3√6=5+6=11