Question

(2х-1)^2=2х-1 решите уравнение

Answer 1

(2X-1)²=2X-1
4x²-4x+1-2x+1=0
4x²-6x+2=0
2(2x²-3+1)=0
2x²-3+1=0
D=3²-4*1*2=9-8=1
$x_{1}= frac{-(-3)- sqrt{1} }{2*2} = frac{3-1}{4} = frac{2}{4} =0.5 \ x_{2}= frac{-(-3)+ sqrt{1} }{2*2} = frac{3+1}{4} = frac{4}{4} =1$