Question

а) 12х(х-3)=(6-х)(х+2)
б) (х+4)(х+1)=х-(х-2)(2-х)

Answer 1

a) 12(x-3)=(6-x)(x+2)
12x - 36 = 6x - x^2 - 2x  +12
x^2 + 8x - 48 = 0
D/4 = 16+48  =64
x1 = -4+8 = 4
x2 = -4 - 8 = -12

б)(x+4)(x+1) = x - (x-2)(2-x)
(x+4)(x+1) = 1 + (x-2)^2
x^2  + 4x  +x  +4 = 1 + x^2 - 4x + 4
5x + 4 = 5 - 4x
9x = -1
x= -1/9