Question

Помогите решить)
1)38sinx=cosx
2)sinx=cosx-1

Answer 1

$38sin x=cos x,|:cos x \ 38tg x=1 \ tg x= frac{1}{38} \ x=arctg frac{1}{38}+ pi n, n in Z$

$sin x=cos x-1 \ cos x-sin x=1 \ sqrt{2} sin(x- frac{ pi }{4} )=1 \ sin(x- frac{ pi }{4} )= frac{1}{ sqrt{2} } \ x-frac{ pi }{4}=(-1)^kcdot frac{ pi }{4}+ pi k, k in Z \ x=(-1)^kcdot frac{ pi }{4}+frac{ pi }{4}+ pi k, k in Z$