Question

1-tg(п-2a)tga/tg(3п/2-a)+tga

Answer 1

(1-tg(π-2α)*tg(α))/((tg(3π/2-α)+tg(α))=(1+tg²α)/(ctg(α)+tg(α))=(tg α + tg³α)/(1+tg²α)