Question

решите уравнение, пожалуйста. очень надо.

Answer 1

$frac{2m}{x} + frac{1}{5} + frac{40}{x+10} - frac{6m}{x}= frac{1}{5} \ frac{2m}{x}- frac{6m}{x} + frac{40}{x+10}=frac{1}{5}-frac{1}{5} \ - frac{4m}{x} + frac{40}{x+10}=0 \ frac{40x-4m(x+10)}{x(x+10)} =0 \ frac{40x-4mx-40m}{x(x+10)} =0 \ left { {{40x-4mx-40m=0} atop {x neq 0}}atop {x neq -10}} right. \ 40x-4mx-40m=0 \ 4(10x-mx-10m)=0 \ 10x-mx-10m=0 \ x(10-m)=10m \ x= frac{10m}{10-m}$