Предмет: Геометрия, автор: nikitakuznetso1

В треугольнике АВС угол А=45, угол В=60, ВС=3 корня из 2. Найдите АС.Если можно с пояснением

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Автор ответа: iranikiv

Пусть в треугольнике ABC AB=с,BC=a,CA=b по формуле a/sina=b/sinb=c/sinc. 3корня из 2/(2корня/2)=b/sin60 6=b/(корень из 3/2) следовательно b(AC) равно 3корня из 3.

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