Question

Решите уравнение:7-(х+ 1 целая 3/5)=2 целых 4/5

Answer 1

7-(х+1$frac{3}{5}$)=2$frac{4}{5}$
7-x-$frac{8}{5}$=$frac{14}{5}$
7-x=$frac{14}5}$+$frac{8}{5}$
7-x=$frac{22}{5}$
-x=$frac{22}{5}$-7
-x=$frac{22-7*5}{5}$
-5x=22-35
5x=13
x=$frac{13}{5}$
x=2$frac{3}{5}$